$A$ galvanometer has resistance '$G$' and range '$V_g$'. How much resistance is required to read voltage up to '$V$' volt?

$A$ $36 \,\Omega$ galvanometer is shunted by a resistance of $4 \,\Omega$. The percentage of the total current that passes through the galvanometer is (in $\%$)

The value of shunt resistance,that allows only $10 \%$ of the main current to pass through a galvanometer of resistance $99 \Omega$,is (in $Omega$)

$A$ galvanometer having a resistance of $20\,\Omega$ and $30\,divisions$ on both sides has a figure of merit of $0.005\,A/division$. The resistance that should be connected in series so that it can be used as a voltmeter up to $15\,V$ is ........... $\Omega$.

$A$ galvanometer of resistance $30 \Omega$ is connected to a battery of emf $2 \text{ V}$ with $1970 \Omega$ resistance in series. $A$ full-scale deflection of $20$ divisions is obtained in the galvanometer. To reduce the deflection to $10$ divisions,the total resistance in series required is: (in $Omega$)

An ammeter has a range of $1 \ A$ without a shunt. The range of the ammeter can be changed by using different shunt resistances. What is the nature of the graph between the shunt resistance and the range?