$A$ $36 \,\Omega$ galvanometer is shunted by a resistance of $4 \,\Omega$. The percentage of the total current that passes through the galvanometer is (in $\%$)

The coil of a moving coil galvanometer has an effective area of $4 \times 10^{-2} \, m^2$. It is suspended in a magnetic field of $5 \times 10^{-2} \, Wb \, m^{-2}$. If the deflection in the galvanometer coil is $0.2 \, rad$, when a current of $5 \, mA$ is passed through it, then

$A$ multirange voltmeter can be constructed by using a galvanometer circuit as shown in the figure. We want to construct a voltmeter that can measure $2 \ V$,$20 \ V$,and $200 \ V$ using a galvanometer of resistance $10 \ \Omega$ that produces maximum deflection for a current of $1 \ mA$. Find $R_1$,$R_2$,and $R_3$ that have to be used.

If only $2 \%$ of the main current is to be passed through a galvanometer of resistance $G$,then the resistance of the shunt connected to it will be:

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is:

Two similar galvanometers are converted into an ammeter and a milliammeter. The shunt resistance of the ammeter as compared to the shunt resistance of the milliammeter will be