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(A) According to the law of conservation of linear momentum,since the body is initially stationary,the total initial momentum is zero.$P_{i} = 0$After

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$\left[\frac{M_{2}}{M_{1}}\right]$

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(A) According to the law of conservation of linear momentum,since the body is initially stationary,the total initial momentum is zero.$P_{i} = 0$After the explosion,the two parts move in opposite directions. Let the velocities be $v_{1}$ and $v_{2}$.$P_{f} = M_{1}v_{1} - M_{2}v_{2} = 0$$M_{1}v_{1} = M_{2}v_{2}$$\frac{v_{1}}{v_{2}} = \frac{M_{2}}{M_{1}}$The kinetic energy of a body is given by $E = \frac{p^{2}}{2M}$. Since the magnitudes of momenta are equal $(p_{1} = p_{2} = p)$,$\frac{E_{1}}{E_{2}} = \frac{p^{2} / (2M_{1})}{p^{2} / (2M_{2})} = \frac{M_{2}}{M_{1}}$Thus,the ratio of their kinetic energies is $\frac{M_{2}}{M_{1}}$.

$A$ stationary body explodes into two parts of masses $M_{1}$ and $M_{2}$. They move in opposite directions with velocities $v_{1}$ and $v_{2}$. The ratio of their kinetic energies is

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