A body falls on a surface of coefficient of r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a body falls from a height $h_1$,its velocity just before impact is $v_b = \sqrt{2gh_1}$.After the collision,the velocity of the body becomes

Vedclass · Accepted Answer

$0.36$

Vedclass · Answer

(B) When a body falls from a height $h_1$,its velocity just before impact is $v_b = \sqrt{2gh_1}$.After the collision,the velocity of the body becomes $v_f = e \cdot v_b$,where $e$ is the coefficient of restitution.The body then rises to a height $h_2$,where $v_f = \sqrt{2gh_2}$.Substituting $v_f$ into the equation,we get $\sqrt{2gh_2} = e \sqrt{2gh_1}$.Squaring both sides,we get $2gh_2 = e^2 (2gh_1)$,which simplifies to $h_2 = e^2 h_1$.Given $e = 0.6$ and $h_1 = 1 \ m$:$h_2 = (0.6)^2 	imes 1 \ m = 0.36 \ m$.

$A$ body falls on a surface of coefficient of restitution $0.6$ from a height of $1 \ m$. Then the body rebounds to a height of (in $m$)

Similar Questions

$A$ ball is moving with speed $20 \, m/s$ collides with a smooth surface as shown in the figure. The magnitude of the change in velocity of the ball will be ........... $m/s$.

In an inelastic collision,after collision the kinetic energy

The quantity that is not conserved in an inelastic collision is

Ball $P$ of mass $m$ moving with velocity $v$ collides with another ball $Q$ of mass $2m$,which is at rest. If $v_P$ and $v_Q$ are the final velocities of $P$ and $Q$ respectively after the collision,then (Assume the coefficient of restitution is $e = 1/3$):

If a body collides inelastically with another body of the same mass initially at rest,what will be the ratio of their speeds after the collision?

Vedclass Test Series

Exam Paper Generator

Online Exam Module