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(C) The efficiency of a transformer is defined as the ratio of output power to input power.$\eta = \frac{	ext{Output Power}}{	ext{Input Power}}$Give

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$90$

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(C) The efficiency of a transformer is defined as the ratio of output power to input power.$\eta = \frac{	ext{Output Power}}{	ext{Input Power}}$Given:Output power $(P_{out})$ = $100 \,W$Input voltage $(V_p)$ = $220 \,V$Input current $(I_p)$ = $0.5 \,A$Input power $(P_{in})$ = $V_p 	imes I_p = 220 \,V 	imes 0.5 \,A = 110 \,W$Efficiency $(\eta)$ = $\frac{100 \,W}{110 \,W} \approx 0.909$$\eta \approx 90.9 \% \approx 90 \%$Thus, the efficiency is approximately $90 \%$.

$A$ transformer is used to light a $100 \,W$ and $110 \,V$ lamp from a $220 \,V$ mains. If the main current is $0.5 \,A$, the efficiency of the transformer is approximately (in $\%$)

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