$A$ $20 \Omega$ resistance,$10 \text{ mH}$ inductance coil,and $15 \mu \text{F}$ capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination,the circuit resonates. If the resistance is made $1/3$ rd of its original value,the resonant frequency:

  • A
    remains unchanged.
  • B
    is doubled.
  • C
    is quadrupled.
  • D
    is halved.

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Similar Questions

In a series resonant $R-L-C$ circuit, the voltage across $R$ is $100 \, V$ and the value of $R = 1000 \, \Omega$. The capacitance of the capacitor is $2 \times 10^{-6} \, F$; the angular frequency of the $AC$ source is $200 \, rad \, s^{-1}$. Then the potential difference across the inductance coil is: (in $V$)

Two circuits are shown in the figures $(a)$ and $(b)$. At a frequency of $....\,rad/s$,the average power dissipated in one cycle will be the same in both circuits.

An $LCR$ circuit as shown in the figure is connected to a voltage source $V_{ac}$ whose frequency can be varied. The frequency,at which the voltage across the resistor is maximum,is......$Hz$.

$A$ resistor of resistance $R$, an inductor of inductive reactance $2R$, and a capacitor of capacitive reactance $X_C$ are connected in series to an $A.C.$ source. If the series $LCR$ circuit is in resonance, then the power factor of the circuit and the value $X_C$ are respectively:

What is resonance in an $LCR$ series circuit?

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