The expression $\log_{e} 2 + \log_{e} \left( 1 + \frac{1}{2} \right) + \log_{e} \left( 1 + \frac{1}{3} \right) + \dots + \log_{e} \left( 1 + \frac{1}{n - 1} \right)$ is equal to
- A$\log_{e} 1$
- B$\log_{e} n$
- C$\log_{e} (1 + n)$
- D$\log_{e} (1 - n)$
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