$\left( {1 + \frac{1}{{2!}} + \frac{1}{{4!}} + \dots} \right) \left( {1 + \frac{1}{{3!}} + \frac{1}{{5!}} + \dots} \right) = $

  • A
    $e^4$
  • B
    $\frac{e^2 - 1}{e^2}$
  • C
    $\frac{e^4 - 1}{4e^2}$
  • D
    $\frac{e^4 + 1}{4e^2}$

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Similar Questions

$b = 1 + \frac{{}^1 C_0 + {}^1 C_1}{1!} + \frac{{}^2 C_0 + {}^2 C_1 + {}^2 C_2}{2!} + \frac{{}^3 C_0 + {}^3 C_1 + {}^3 C_2 + {}^3 C_3}{3!} + \ldots$
माना $a = 1 + \frac{{}^2 C_2}{3!} + \frac{{}^3 C_2}{4!} + \frac{{}^4 C_2}{5!} + \ldots$. तो $\frac{2b}{a^2}$ का मान ज्ञात कीजिए।

श्रेणी $1 + \frac{x^2}{2!} + \frac{x^4}{4!} + \dots$ का अनंत तक योग क्या है?

$\frac{2}{3!} + \frac{4}{5!} + \frac{6}{7!} + \dots \infty = $

$\frac{x^2 - y^2}{1!} + \frac{x^4 - y^4}{2!} + \frac{x^6 - y^6}{3!} + \dots \infty = $

$\frac{1-2x}{e^x}$ में $x^n$ का गुणांक क्या है?

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