A bullet is shot horizontally and its distanc | vedclass

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(B) The distance equation is given by $S = 1200t - 15t^2$. To find the velocity $v$, we differentiate $S$ with respect to $t$: $v = \frac{dS}{dt} = \f

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$24000$

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(B) The distance equation is given by $S = 1200t - 15t^2$. To find the velocity $v$, we differentiate $S$ with respect to $t$: $v = \frac{dS}{dt} = \frac{d}{dt}(1200t - 15t^2) = 1200 - 30t$. When the bullet comes to rest, its velocity $v$ becomes $0$: $1200 - 30t = 0$ $30t = 1200$ $t = 40 	ext{ seconds}$. Now, substitute $t = 40$ into the distance equation to find the total distance covered: $S = 1200(40) - 15(40)^2$ $S = 48000 - 15(1600)$ $S = 48000 - 24000$ $S = 24000 	ext{ cm}$.

$A$ bullet is shot horizontally and its distance $S$ cm at time $t$ second is given by $S=1200t-15t^2$. Then, the distance covered by the bullet when it comes to rest is: (in $\text{ cm}$)

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