A gas absorbs 150 J of heat and expands by 3 | vedclass

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(B) Given: Heat absorbed $(q)$ = $+150 \ J$ (since heat is absorbed by the system). External pressure $(P_{ext})$ = $2 	imes 10^5 \ N \ m^{-2}$. Chan

Vedclass · Accepted Answer

$90$

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(B) Given: Heat absorbed $(q)$ = $+150 \ J$ (since heat is absorbed by the system). External pressure $(P_{ext})$ = $2 	imes 10^5 \ N \ m^{-2}$. Change in volume $(\Delta V)$ = $300 \ cm^3 = 300 	imes 10^{-6} \ m^3 = 3 	imes 10^{-4} \ m^3$. Work done $(W)$ = $-P_{ext} 	imes \Delta V$. $W = -(2 	imes 10^5 \ N \ m^{-2}) 	imes (3 	imes 10^{-4} \ m^3) = -60 \ J$. According to the first law of thermodynamics: $\Delta U = q + W$. $\Delta U = 150 \ J + (-60 \ J) = 90 \ J$.

$A$ gas absorbs $150 \ J$ of heat and expands by $300 \ cm^3$ against a constant external pressure of $2 \times 10^5 \ N \ m^{-2}$. What is the change in internal energy $(\Delta U)$ of the system (in $J$)?

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