For which reaction is Delta H neq Delta U? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by the equation: $\Delta H = \Delta U + \De

Vedclass · Accepted Answer

$N_{2(g)} + 3 H_{2(g)} \longrightarrow 2 NH_{3(g)}$

Vedclass · Answer

(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by the equation: $\Delta H = \Delta U + \Delta n_g RT$,where $\Delta n_g$ is the change in the number of moles of gaseous products and reactants.For $\Delta H 
eq \Delta U$,we must have $\Delta n_g 
eq 0$.$(A)$ $\Delta n_g = 2 - (1 + 1) = 0$.$(B)$ $\Delta n_g = (1 + 1) - 2 = 0$.$(C)$ $\Delta n_g = 2 - (1 + 3) = 2 - 4 = -2$. Since $\Delta n_g 
eq 0$,$\Delta H 
eq \Delta U$.$(D)$ $\Delta n_g = 1 - (0 + 1) = 0$ (Note: $C_{(s)}$ is a solid,so its moles are not counted in $\Delta n_g$).Therefore,the correct option is $C$.

For which reaction is $\Delta H \neq \Delta U$?

Similar Questions

What is the change in internal energy if a system does $140 \ kJ$ of work on the surroundings and $40 \ kJ$ of heat is added to the system (in $kJ$)?

For the reaction $PCl_{5(g)} \to PCl_{3(g)} + Cl_{2(g)}$,which of the following relations is correct?

Assertion : For a reaction $2NH_{3(g)} \to N_{2(g)} + 3H_{2(g)}$ ; $\Delta H > \Delta E$.
Reason : Enthalpy change is always greater than internal energy change.

At constant $T$ and $P$,which one of the following statements is correct for the reaction,$CO_{(g)} + \frac{1}{2} O_{2(g)} \to CO_{2(g)}$?

Which of the following statements is true regarding the universe according to the laws of thermodynamics?

Vedclass Test Series

Exam Paper Generator

Online Exam Module