(C) For a first order reaction,the rate law is given by $-\frac{d[A]}{dt} = k[A]$.Integrating this expression from time $t=0$ (where $[A] = a$) to tim

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$k = \frac{2.303}{t} \log \frac{a}{a-x}$

(C) For a first order reaction,the rate law is given by $-\frac{d[A]}{dt} = k[A]$.Integrating this expression from time $t=0$ (where $[A] = a$) to time $t$ (where $[A] = a-x$),we get:$k = \frac{2.303}{t} \log \frac{a}{a-x}$where '$a$' is the initial concentration and '$a-x$' is the concentration at time '$t$'.

Class 12 Chemistry Chemical Kinetics First Order reaction

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$A$ first order reaction is given as $A \rightarrow \text{products}$. Its integrated rate equation is:

MHT CET 2011 All MHT CET

A
$k = \frac{2.303}{t} \log \frac{a-x}{a}$
B
$k = \frac{1}{t} \log \frac{a}{a-x}$
C
$k = \frac{2.303}{t} \log \frac{a}{a-x}$
D
$-k = \frac{1}{t} \log \frac{a-x}{a}$

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For a first order gas phase reaction:
$A_{(g)} \rightarrow 2 B_{(g)} + C_{(g)}$
Let $P_0$ be the initial pressure of $A$ and $P_t$ be the total pressure at time $t$. The integrated rate equation is:

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What is the half-life time of a first-order reaction if the initial concentration of the reactant is $0.01 \ mol \ L^{-1}$ and the rate of reaction is $0.00352 \ mol \ L^{-1} \ minute^{-1}$?

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For a first-order reaction,if the value of $a/(a - x)$ is $8$ after $10 \text{ minutes}$,what will be the rate constant $K$?

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For a first order reaction,a plot of $\log(a-x)$ against time is a straight line with negative slope equal to

MediumAIIMS 2019

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The half-life period for a first order reaction is $693 \ sec$. The rate constant for this reaction would be: (in $sec^{-1}$)

Medium

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$A$ first order reaction is given as $A \rightarrow \text{products}$. Its integrated rate equation is:

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For a first order gas phase reaction: $A_{(g)} \rightarrow 2 B_{(g)} + C_{(g)}$ Let $P_0$ be the initial pressure of $A$ and $P_t$ be the total pressure at time $t$. The integrated rate equation is:

What is the half-life time of a first-order reaction if the initial concentration of the reactant is $0.01 \ mol \ L^{-1}$ and the rate of reaction is $0.00352 \ mol \ L^{-1} \ minute^{-1}$?

For a first-order reaction,if the value of $a/(a - x)$ is $8$ after $10 \text{ minutes}$,what will be the rate constant $K$?

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For a first order gas phase reaction:
$A_{(g)} \rightarrow 2 B_{(g)} + C_{(g)}$
Let $P_0$ be the initial pressure of $A$ and $P_t$ be the total pressure at time $t$. The integrated rate equation is: