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(D) Colour blindness is an $X$-linked recessive disorder.Let $X^C$ represent the allele for colour blindness and $X$ represent the normal allele.The h

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(D) Colour blindness is an $X$-linked recessive disorder.Let $X^C$ represent the allele for colour blindness and $X$ represent the normal allele.The husband has normal vision,so his genotype is $XY$.The wife has normal vision,but her father was colour blind. Therefore,she must be a carrier,with the genotype $X^CX$.The cross is: $XY 	imes X^CX$.The possible genotypes of the offspring are: $XX$ (normal daughter),$X^CX$ (carrier daughter),$XY$ (normal son),and $X^CY$ (colour blind son).For a daughter to be colour blind,she must inherit the $X^C$ allele from both parents. Since the father is normal $(XY)$,he cannot pass the $X^C$ allele to his daughter.Therefore,the probability of their daughter being colour blind is $0 \%$.

$A$ husband and wife have normal vision,but the fathers of both of them were colour blind. What is the probability of their first daughter being colour blind (in $\%$)?

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