CH_3-CH=CH-CH=CH_2 xrightarrow[Zn]{O_3 / H_2O | vedclass

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Question

(B) The ozonolysis of $CH_3-CH=CH-CH=CH_2$ involves the cleavage of both double bonds.Step $1$: The first double bond $(CH_3-CH=CH-)$ cleaves to form

Vedclass · Accepted Answer

$CH_3-CH_2-CHO$

Vedclass · Answer

(B) The ozonolysis of $CH_3-CH=CH-CH=CH_2$ involves the cleavage of both double bonds.Step $1$: The first double bond $(CH_3-CH=CH-)$ cleaves to form $CH_3-CHO$ and $OHC-$.Step $2$: The second double bond $(-CH=CH_2)$ cleaves to form $OHC-$ and $HCHO$.Step $3$: Combining the fragments,the products are $CH_3-CHO$,$OHC-CHO$ (glyoxal),and $HCHO$.Therefore,$CH_3-CH_2-CHO$ is not formed.

$CH_3-CH=CH-CH=CH_2 \xrightarrow[Zn]{O_3 / H_2O}$ Which will not form?

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