What is X in the following reaction? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction shows that $C_6H_{10}$ (cyclohexene) reacts with $KMnO_4-H_2SO_4$ to form adipic acid (hexanedioic acid),which is a standard ox

Vedclass · Accepted Answer

$3-$bromocyclohex$-1-$ene

Vedclass · Answer

(A) The given reaction shows that $C_6H_{10}$ (cyclohexene) reacts with $KMnO_4-H_2SO_4$ to form adipic acid (hexanedioic acid),which is a standard oxidative cleavage reaction of cyclohexene. When cyclohexene $(C_6H_{10})$ reacts with $Br_2$ in the presence of $UV$ light,it undergoes allylic bromination. The allylic position in cyclohexene is the carbon adjacent to the double bond. Therefore,the product $X$ is $3$-bromocyclohex-$1$-ene.

What is $X$ in the following reaction?

Similar Questions

On vigorous oxidation by permanganate solution,$(CH_3)_2C = CH - CH_2CH_2CH_3$ gives:

The product obtained by the reaction of $1,2$-dibromoethane with zinc metal at high temperature is........

When ethene reacts with bromine,it forms

Predict the major product for the following reaction:
$CH_2=CH-CH_2-I \xrightarrow{HI \text{ (Excess)}} ?$

The number of alkenyl groups possible from $C_{4}H_{7}$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module