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(B) When the ball moves with a constant terminal velocity,its acceleration is zero $(a = 0)$.According to Newton's second law,the net force acting on

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$\frac{Mg}{2}$

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(B) When the ball moves with a constant terminal velocity,its acceleration is zero $(a = 0)$.According to Newton's second law,the net force acting on the ball is zero.The forces acting on the ball are:$1$. Weight of the ball $(Mg)$ acting downwards.$2$. Buoyant force $(F_B)$ acting upwards.$3$. Viscous force $(f)$ acting upwards.Equating the forces:$Mg = F_B + f$$f = Mg - F_B$The buoyant force is given by $F_B = V \rho_{glycerine} g$,where $V$ is the volume of the ball.Since $M = V \rho_{ball}$,we have $V = \frac{M}{\rho_{ball}}$.Given $\rho_{glycerine} = \frac{1}{2} \rho_{ball}$,we get:$F_B = V (\frac{1}{2} \rho_{ball}) g = \frac{1}{2} (V \rho_{ball}) g = \frac{Mg}{2}$.Substituting this into the force equation:$f = Mg - \frac{Mg}{2} = \frac{Mg}{2}$.

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