A relation R is defined from {2, 3, 4, 5} to | vedclass

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(D) Two numbers are relatively prime if their greatest common divisor $(GCD)$ is $1$.We check each element $x \in \{2, 3, 4, 5\}$ to see if there exis

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$\{2, 3, 4, 5\}$

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(D) Two numbers are relatively prime if their greatest common divisor $(GCD)$ is $1$.We check each element $x \in \{2, 3, 4, 5\}$ to see if there exists at least one $y \in \{3, 6, 7, 10\}$ such that $	ext{gcd}(x, y) = 1$:- For $x = 2$: $	ext{gcd}(2, 3) = 1$,so $(2, 3) \in R$.- For $x = 3$: $	ext{gcd}(3, 7) = 1$,so $(3, 7) \in R$.- For $x = 4$: $	ext{gcd}(4, 3) = 1$,so $(4, 3) \in R$.- For $x = 5$: $	ext{gcd}(5, 3) = 1$,so $(5, 3) \in R$.Since every element in the set $\{2, 3, 4, 5\}$ is related to at least one element in $\{3, 6, 7, 10\}$,the domain of $R$ is $\{2, 3, 4, 5\}$.

$A$ relation $R$ is defined from $\{2, 3, 4, 5\}$ to $\{3, 6, 7, 10\}$ by $xRy \iff x$ is relatively prime to $y$. Then the domain of $R$ is

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