K is the force constant of a spring. The work | vedclass

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Question

(d) At extension ${l_1}$, the stored energy $ = \frac{1}{2}Kl_1^2$

At extension ${l_2}$, the stored energy$ = \frac{1}{2}Kl_2^2$

Work done in in

Vedclass · Accepted Answer

$\frac{K}{2}(l_2^2 - l_1^2)$

Vedclass · Answer

(d) At extension ${l_1}$, the stored energy $ = \frac{1}{2}Kl_1^2$

At extension ${l_2}$, the stored energy$ = \frac{1}{2}Kl_2^2$

Work done in increasing its extension from ${l_1}$ to ${l_2}$

                 $ = \frac{1}{2}K(l_2^2 - l_1^2)$

$K$ is the force constant of a spring. The work done in increasing its extension from ${l_1}$ to ${l_2}$ will be

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