$50 \,g$ ice at $0^{\circ} C$ is dropped into a calorimeter containing $100 \,g$ water at $30^{\circ} C$. If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is .......... $g$
$12.5$
$25$
$20$
$10$
$50\, gm$ of copper is heated to increase its temperature by $10^oC$. If the same quantity of heat is given to $10\; gm$ of water, the rise in its temperature is ........ $^oC$ (Specific heat of copper $= 420 \;Joule-kg^{-1} {°C^{-1}}$)
$10\,gm$ of ice at $0\,^oC$ is mixed with $'m'\,gm$ of water at $50\,^oC$ . ........ $gm$ is minimum value of $m$ so that ice melts completely. ( $L_f = 80\,cal/gm$ and $S_W = 1\,cal/gm-\,^oC$ )
Boiling water is changing into steam. Under this condition, the specific heat of water is
$10 \,\,gm$ of ice at $0^o C$ is kept in a calorimeter of water equivalent $10 \,\,gm$. ....... $cal$ heat should be supplied to the apparatus to evaporate the water thus formed? (Neglect loss of heat)
An electric kettle (rated accurately at $2.5\, kW$) is used to heat $3\, kg$ of water from $15\,^oC$ to boiling point. It takes $9.5$ minute. Then, the amount of heat that has been lost is