$2,3$-dibromobutane can be converted to $2$-butyne in a two-step reaction using:

  • A
    $(i) \ HCl$ and $(ii) \ NaH$
  • B
    $(i) \ \text{alc. } KOH$ and $(ii) \ NaNH_2$
  • C
    $(i) \ Na$ and $(ii) \ NaOH$
  • D
    $(i) \ Br_2$ and $(ii) \ NaH$

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