The reaction Ph-C equiv CH xrightarrow[{(2),H | vedclass

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(C) The reaction of a terminal alkyne with $BH_3.THF$ followed by oxidation with $H_2O_2/OH^-$ is a hydroboration-oxidation reaction. This reaction fo

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$Ph-CH_2-CHO$

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(C) The reaction of a terminal alkyne with $BH_3.THF$ followed by oxidation with $H_2O_2/OH^-$ is a hydroboration-oxidation reaction. This reaction follows anti-Markovnikov addition of water across the triple bond. For a terminal alkyne like $Ph-C \equiv CH$,the initial product is an enol,$Ph-CH=CH-OH$. This enol tautomerizes to form an aldehyde. Therefore,the final product is $Ph-CH_2-CHO$ (phenylacetaldehyde).

The reaction $Ph-C \equiv CH \xrightarrow[{(2)\,H_2O_2/OH^{-}}]{{(1)\,BH_3.THF}}$ Product; the product is

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