CH_3-CH=CH-CH(OH)-CH_3 xrightarrow{text{Jones | vedclass

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(B) The Jones reagent ($CrO_3$ in $H_2SO_4/H_2O$) is a strong oxidizing agent used for the oxidation of alcohols.It oxidizes primary alcohols to carbo

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$CH_3CH=CHCOCH_3$

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(B) The Jones reagent ($CrO_3$ in $H_2SO_4/H_2O$) is a strong oxidizing agent used for the oxidation of alcohols.It oxidizes primary alcohols to carboxylic acids and secondary alcohols to ketones.The given substrate is $pent-3-en-2-ol$,which is an allylic secondary alcohol.Jones reagent oxidizes the secondary alcohol group $(-CH(OH)-)$ to a ketone group $(-C=O)$ without affecting the carbon-carbon double bond $(C=C)$ under standard conditions.Therefore,the reaction is:$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{Jones \ reagent} CH_3-CH=CH-COCH_3$The product $X$ is $pent-3-en-2-one$ $(CH_3CH=CHCOCH_3)$.

Column-$I$ (Example)	Column-$II$ (Reaction)
$(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$	$(1)$ Friedel-Crafts acylation
$(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$	$(2)$ $HVZ$ reaction
$(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$	$(3)$ Aldol condensation
$(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$	$(4)$ Cannizzaro's reaction
$(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$	$(5)$ Rosenmund's reduction
$(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$	$(6)$ Stephen's reaction

$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{\text{Jones reagent}} X$,
Product $X$ is

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$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{\text{Jones reagent}} X$,Product $X$ is