$C_2H_5MgI$ reacts with $HCHO$ to form the final product.
- A$CH_3CHO$
- B$C_3H_7OH$
- C$CH_3COCH_3$
- D$CH_3COOCH_3$
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Similar Questions
What are $X$ and $Y$ in the following reactions?
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$
In the following reaction,$'A'$ is:
$C_2H_5MgBr + CH_2(O)CH_2 \xrightarrow{H_2O} A$
$C_2H_5MgBr + CH_2(O)CH_2 \xrightarrow{H_2O} A$
MediumAIPMT 1998
View SolutionExplain the process of obtaining alcohols from aldehydes and ketones with examples.
Medium
View SolutionThe product of the following reaction is ...............
$(CH_3)_3C-CH=CH_2 \xrightarrow[(ii) \, NaBH_4 + NaOH]{(i) \, Hg(CH_3COO)_2; \, THF} ?$
$(CH_3)_3C-CH=CH_2 \xrightarrow[(ii) \, NaBH_4 + NaOH]{(i) \, Hg(CH_3COO)_2; \, THF} ?$
Difficult
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