C_6H_5Cl is prepared from aniline by: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The preparation of chlorobenzene $(C_6H_5Cl)$ from aniline involves two main steps: $1$. Diazotization: Aniline reacts with $HNO_2$ (prepared in s

Vedclass · Accepted Answer

Treatment with $HNO_2$ followed by heating with $Cu_2Cl_2$

Vedclass · Answer

(D) The preparation of chlorobenzene $(C_6H_5Cl)$ from aniline involves two main steps: $1$. Diazotization: Aniline reacts with $HNO_2$ (prepared in situ from $NaNO_2 + HCl$) at $0-5 \ ^\circ C$ to form benzene diazonium chloride. $2$. Sandmeyer reaction: The benzene diazonium chloride is then treated with cuprous chloride $(Cu_2Cl_2)$ in the presence of $HCl$ to yield chlorobenzene,with the evolution of nitrogen gas $(N_2)$.

$C_6H_5Cl$ is prepared from aniline by:

Similar Questions

Fluorobenzene $(C_6H_5F)$ can be synthesized in the laboratory

The number of halobenzenes from the following that can be prepared by Sandmeyer's reaction is . . . . . . . . .

What is the name of the following reaction?
$ArN_2^+X^- + Cu_2Cl_2 + HCl \rightarrow \text{Chlorobenzene} + N_2$

Which among the following is true for the Balz-Schiemann reaction?

How will you obtain monobromobenzene from aniline?

Vedclass Test Series

Exam Paper Generator

Online Exam Module