How will you obtain monobromobenzene from aniline?

(N/A) To obtain monobromobenzene from aniline,the following two-step process is used:
$1$. Diazotization: Aniline is treated with $NaNO_2$ and $HCl$ at a low temperature of $273-278 \ K$ to form benzene diazonium chloride.
$2$. Sandmeyer's Reaction: The benzene diazonium chloride is then treated with cuprous bromide $(Cu_2Br_2)$ in the presence of hydrobromic acid $(HBr)$ to yield bromobenzene.
The reaction sequence is:
$C_6H_5NH_2$ $\xrightarrow{NaNO_2 + HCl, 273-278 \ K} C_6H_5N_2^+Cl^-$ $\xrightarrow{Cu_2Br_2/HBr} C_6H_5Br$