15 mL of aqueous solution of Fe^{2+} in acid | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The balanced redox reaction in acidic medium is: $6Fe^{2+} + Cr_{2}O_{7}^{2-} + 14H^+ \rightarrow 6Fe^{3+} + 2Cr^{3+} + 7H_{2}O$. According to the

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(C) The balanced redox reaction in acidic medium is: $6Fe^{2+} + Cr_{2}O_{7}^{2-} + 14H^+ ightarrow 6Fe^{3+} + 2Cr^{3+} + 7H_{2}O$. According to the law of equivalence,the number of equivalents of $Fe^{2+}$ equals the number of equivalents of $Cr_{2}O_{7}^{2-}$. $n_{eq} (Fe^{2+}) = n_{eq} (Cr_{2}O_{7}^{2-})$. $(Molarity 	imes Volume 	imes n-factor)_{Fe^{2+}} = (Molarity 	imes Volume 	imes n-factor)_{Cr_{2}O_{7}^{2-}}$. For $Fe^{2+} ightarrow Fe^{3+}$,the $n-factor = 1$. For $Cr_{2}O_{7}^{2-} ightarrow 2Cr^{3+}$,the $n-factor = 6$. $\left(\frac{15 	imes M_{Fe^{2+}}}{1000}ight) 	imes 1 = \left(\frac{20 	imes 0.03}{1000}ight) 	imes 6$. $15 	imes M_{Fe^{2+}} = 20 	imes 0.03 	imes 6$. $15 	imes M_{Fe^{2+}} = 3.6$. $M_{Fe^{2+}} = \frac{3.6}{15} = 0.24 \ M$. $0.24 \ M = 24 	imes 10^{-2} \ M$. Thus,the value is $24$.

$15 \ mL$ of aqueous solution of $Fe^{2+}$ in acidic medium completely reacted with $20 \ mL$ of $0.03 \ M$ aqueous $Cr_{2}O_{7}^{2-}$. The molarity of the $Fe^{2+}$ solution is ........... $\times 10^{-2} \ M$ (Round off to the Nearest Integer).

Similar Questions

What is a redox reaction? Explain its uses.

In which of the following reactions is there no change in the valency (oxidation state) of the elements?

Equivalent weights of $KMnO_4$ and $K_2Cr_2O_7$ in acidic medium are respectively. (Molecular weight of $KMnO_4 = M_A$ and Molecular weight of $K_2Cr_2O_7 = M_B$).

Among $C$,$S$,and $P$,the element$(s)$ that produce$(s)$ $SO_{2}$ on reaction with hot conc. $H_{2}SO_{4}$ is / are

Consider the reactions:
$2S_2O_3^{2-}(aq) + I_2(s) \to S_4O_6^{2-}(aq) + 2I^-(aq)$
$S_2O_3^{2-}(aq) + 2Br_2(l) + 5H_2O(l) \to 2SO_4^{2-}(aq) + 4Br^-(aq) + 10H^+(aq)$
Why does the same reductant,thiosulphate,react differently with iodine and bromine?

Vedclass Test Series

Exam Paper Generator

Online Exam Module