A uniform rod of mass M and length L is place | vedclass

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(A) The acceleration of the centre of mass of a system is given by the formula: $a_{cm} = \frac{F_{ext}}{M_{total}}$.Here,the external force applied t

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$F/M$

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(A) The acceleration of the centre of mass of a system is given by the formula: $a_{cm} = \frac{F_{ext}}{M_{total}}$.Here,the external force applied to the rod is $F$ and the total mass of the rod is $M$.Therefore,the acceleration of the centre of mass is $a_{cm} = \frac{F}{M}$.This acceleration is independent of the point of application of the force,as the centre of mass moves as if the entire mass were concentrated at that point and the force were applied there.

$A$ uniform rod of mass $M$ and length $L$ is placed on a smooth horizontal surface. $A$ horizontal force $F$ is applied at one end of the rod perpendicular to its length. The acceleration of the centre of mass of the rod is:

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