If $3 \sin \theta = 4 \cos \theta$,then $\tan \theta = \ldots$

  • A
    $\frac{3}{2}$
  • B
    $\frac{2}{3}$
  • C
    $\frac{3}{4}$
  • D
    $\frac{4}{3}$

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Show that $\tan ^{4} \theta+\tan ^{2} \theta=\sec ^{4} \theta-\sec ^{2} \theta$

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