If $\tan A = \cot B$,then $A + B = \ldots$
- A$30$
- B$60$
- C$90$
- D$180$
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Similar Questions
Which of the following pairs is correct for trigonometric inter-relationships?
$1. \cos \theta$ $a. \frac{\cos \theta}{\sin \theta}$ $2. \tan \theta$ $b. \frac{1}{\csc \theta}$ $3. \cot \theta$ $c. \frac{1}{\sec \theta}$ $4. \sin \theta$ $d. \frac{1}{\cot \theta}$ $e. \sin \theta \cdot \cos \theta$
| $1. \cos \theta$ | $a. \frac{\cos \theta}{\sin \theta}$ |
| $2. \tan \theta$ | $b. \frac{1}{\csc \theta}$ |
| $3. \cot \theta$ | $c. \frac{1}{\sec \theta}$ |
| $4. \sin \theta$ | $d. \frac{1}{\cot \theta}$ |
| $e. \sin \theta \cdot \cos \theta$ |
Easy
View SolutionProve that,$(\sin \alpha+\cos \alpha)(\tan \alpha+\cot \alpha)=\sec \alpha+\operatorname{cosec} \alpha$
Medium
View SolutionWrite 'True' or 'False' and justify your answer.
$\cos \theta = \frac{a^{2} + b^{2}}{2ab}$,where $a$ and $b$ are two distinct numbers such that $ab > 0$.
$\cos \theta = \frac{a^{2} + b^{2}}{2ab}$,where $a$ and $b$ are two distinct numbers such that $ab > 0$.
Medium
View SolutionIf $\sec \theta = \frac{5}{3}$,then $\tan \theta = \ldots$
Easy
View Solution$\sin (45^{\circ}+\theta)-\cos (45^{\circ}-\theta)$ is equal to
Easy
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