$\sin \theta \cdot \cos (90^\circ - \theta) = \ldots \ldots \ldots$
- A$\tan \theta$
- B$\sin^2 \theta$
- C$\cos^2 \theta$
- D$\sin \theta \cdot \sec \theta$
Explore More
Similar Questions
Write 'True' or 'False' and justify your answer.
$(\tan \theta+2)(2 \tan \theta+1)=5 \tan \theta+\sec ^{2} \theta$
$(\tan \theta+2)(2 \tan \theta+1)=5 \tan \theta+\sec ^{2} \theta$
Easy
View SolutionIf $\tan A = \cot B$,then $A + B = \ldots$
Easy
View SolutionIf $\operatorname{cosec} \theta = \frac{2}{\sqrt{3}}$,then $\theta = \ldots$ (in $^\circ$)
Easy
View SolutionIf $\sin \theta = \frac{1}{2}$,then $\theta = \ldots \ldots \ldots \ldots$ (in $^\circ$)
Easy
View Solution$\sin (90^\circ - \theta) = \ldots \ldots \ldots$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo