If A(x_1, y_1), B(x_2, y_2), and C(x_3, y_3) | vedclass

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(C) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2),$ and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(

Vedclass · Accepted Answer

$\frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$

Vedclass · Answer

(C) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2),$ and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$.This formula is derived from the shoelace formula or by calculating the area of trapezoids formed by dropping perpendiculars from the vertices to the $x$-axis.Comparing this with the given options,option $C$ is the correct representation.

If $A(x_1, y_1), B(x_2, y_2),$ and $C(x_3, y_3)$ are the vertices of $\Delta ABC,$ then the area of $\Delta ABC$ is equal to:

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