overline{AB} is a diameter of odot(P, r). If | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The center $P$ of a circle is the midpoint of its diameter $\overline{AB}$.Given $A(x_1, y_1) = (4, 0)$ and $B(x_2, y_2) = (-2, 2)$.The midpoint f

Vedclass · Accepted Answer

$(1, 1)$

Vedclass · Answer

(A) The center $P$ of a circle is the midpoint of its diameter $\overline{AB}$.Given $A(x_1, y_1) = (4, 0)$ and $B(x_2, y_2) = (-2, 2)$.The midpoint formula is $P(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$.Substituting the values: $P(x, y) = \left( \frac{4 + (-2)}{2}, \frac{0 + 2}{2} \right)$.$P(x, y) = \left( \frac{2}{2}, \frac{2}{2} \right) = (1, 1)$.Therefore,the coordinates of $P$ are $(1, 1)$.

$\overline{AB}$ is a diameter of $\odot(P, r)$. If $A(4, 0)$ and $B(-2, 2)$ are given,then the coordinates of $P$ are.............

Similar Questions

Given points $A(3, 4)$ and $B(5, -2)$. Find the point $P(x, y)$ on the plane such that $PA = PB$ and the area of $\Delta PAB = 10$.

Using the distance formula,show that the points $A(7,3)$,$B(3,0)$,$C(0,-4)$,and $D(4,-1)$ are the vertices of a rhombus.

If $A (3,0), B (0,0), C (1,3)$ and $D (4,3),$ then $\square ABCD$ is a $\ldots \ldots \ldots \ldots$

The distance between the points $A(2, 3)$ and $B(-3, -9)$ is ...........

For points $A(1, 7)$,$B(2, 4)$,and $C(k, 5)$,if $\angle A = 90^\circ$,then find the value of $k$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module