$\cos (40^{\circ}-\theta)-\sin (50^{\circ}+\theta) = \ldots \ldots \ldots \ldots$
- A$\sin 40^{\circ}$
- B$\sin 10^{\circ}$
- C$2$
- D$0$
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Write 'True' or 'False' and justify your answer.
$\cos \theta = \frac{a^{2} + b^{2}}{2ab}$,where $a$ and $b$ are two distinct numbers such that $ab > 0$.
$\cos \theta = \frac{a^{2} + b^{2}}{2ab}$,where $a$ and $b$ are two distinct numbers such that $ab > 0$.
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View SolutionIf $\tan ^{2} \theta = \sin ^{2} \theta + \cos ^{2} \theta$ and $0 < \theta < 90^{\circ}$,then the value of $\theta$ is ...... (in $^{\circ}$)
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