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(A) In Mendel's dihybrid cross,the $F_1$ generation is heterozygous for two traits,represented as $RrYy$.According to the Law of Independent Assortmen

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$25$

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(A) In Mendel's dihybrid cross,the $F_1$ generation is heterozygous for two traits,represented as $RrYy$.According to the Law of Independent Assortment,the alleles of two different genes segregate independently during gamete formation.For the genotype $RrYy$,the possible gametes produced are $RY$,$Ry$,$rY$,and $ry$.Each of these four types of gametes is produced in equal proportions.Therefore,the proportion of each type of gamete is $1/4$ or $25 \%$.

In Mendel's dihybrid cross experiment,when $F_1$ generation plants are self-pollinated,what is the proportion of each type of gamete produced (in $\%$)?

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