I. 24x^2 + 38x + 15 = 0II. 12y^2 + 28y + 15 = | vedclass

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(C) For equation $I: 24x^2 + 38x + 15 = 0$$24x^2 + 20x + 18x + 15 = 0$$4x(6x + 5) + 3(6x + 5) = 0$$(4x + 3)(6x + 5) = 0$$x = -\frac{3}{4} = -0.75$ and

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$x \geq y$

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(C) For equation $I: 24x^2 + 38x + 15 = 0$$24x^2 + 20x + 18x + 15 = 0$$4x(6x + 5) + 3(6x + 5) = 0$$(4x + 3)(6x + 5) = 0$$x = -\frac{3}{4} = -0.75$ and $x = -\frac{5}{6} \approx -0.833$For equation $II: 12y^2 + 28y + 15 = 0$$12y^2 + 18y + 10y + 15 = 0$$6y(2y + 3) + 5(2y + 3) = 0$$(6y + 5)(2y + 3) = 0$$y = -\frac{5}{6} \approx -0.833$ and $y = -\frac{3}{2} = -1.5$Comparing the values:$x_1 = -0.75, x_2 = -0.833$$y_1 = -0.833, y_2 = -1.5$Since $-0.75 > -0.833$,$-0.75 > -1.5$,$-0.833 = -0.833$,and $-0.833 > -1.5$,we conclude that $x \geq y$.

$I. 24x^2 + 38x + 15 = 0$
$II. 12y^2 + 28y + 15 = 0$

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$I. 24x^2 + 38x + 15 = 0$$II. 12y^2 + 28y + 15 = 0$