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(B) For equation $I$: $2x^2 + 23x + 63 = 0$We factorize the quadratic equation: $2x^2 + 14x + 9x + 63 = 0$$2x(x + 7) + 9(x + 7) = 0$$(2x + 9)(x + 7) =

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if $x < y$

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(B) For equation $I$: $2x^2 + 23x + 63 = 0$We factorize the quadratic equation: $2x^2 + 14x + 9x + 63 = 0$$2x(x + 7) + 9(x + 7) = 0$$(2x + 9)(x + 7) = 0$So,$x = -4.5$ or $x = -7$.For equation $II$: $4y^2 + 19y + 21 = 0$We factorize the quadratic equation: $4y^2 + 12y + 7y + 21 = 0$$4y(y + 3) + 7(y + 3) = 0$$(4y + 7)(y + 3) = 0$So,$y = -1.75$ or $y = -3$.Comparing the values:$x_1 = -4.5, x_2 = -7$$y_1 = -1.75, y_2 = -3$Since both values of $x$ are less than both values of $y$ ($-7 < -3$ and $-4.5 < -1.75$),we conclude that $x < y$.

Solve the given two equations and select the correct option.
$I.$ $2x^2 + 23x + 63 = 0$
$II.$ $4y^2 + 19y + 21 = 0$

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Solve the given two equations and select the correct option.$I.$ $2x^2 + 23x + 63 = 0$$II.$ $4y^2 + 19y + 21 = 0$