171 g of cane sugar (C_{12}H_{22}O_{11}) is | vedclass

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(C) The molar mass of cane sugar $(C_{12}H_{22}O_{11})$ is $12 	imes 12 + 22 	imes 1 + 11 	imes 16 = 144 + 22 + 176 = 342 \ g/mol$.Molarity $(M)$ i

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$0.5$

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(C) The molar mass of cane sugar $(C_{12}H_{22}O_{11})$ is $12 	imes 12 + 22 	imes 1 + 11 	imes 16 = 144 + 22 + 176 = 342 \ g/mol$.Molarity $(M)$ is defined as the number of moles of solute per liter of solution.Number of moles of cane sugar = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{171 \ g}{342 \ g/mol} = 0.5 \ mol$.Molarity = $\frac{	ext{Moles of solute}}{	ext{Volume of solution in } L} = \frac{0.5 \ mol}{1 \ L} = 0.5 \ M$.

$171 \ g$ of cane sugar $(C_{12}H_{22}O_{11})$ is dissolved in $1 \ L$ of water. The molarity of the solution is ......... $M$.

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[Atomic mass : $H: 1.0, C: 12.0, O: 16.0]$

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