The mole fraction of a solute in a 1 molal et | vedclass

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Question

(C) $1$ molal solution means $1$ mole of solute is dissolved in $1000 \ g$ $(1 \ kg)$ of ethanol.Molecular weight of ethanol $(C_2H_5OH)$ = $(2 	imes

Vedclass · Accepted Answer

$0.044$

Vedclass · Answer

(C) $1$ molal solution means $1$ mole of solute is dissolved in $1000 \ g$ $(1 \ kg)$ of ethanol.Molecular weight of ethanol $(C_2H_5OH)$ = $(2 	imes 12.01) + (6 	imes 1.008) + 16.00 = 46.07 \ g/mol$.Number of moles of ethanol = $\frac{1000 \ g}{46.07 \ g/mol} \approx 21.70 \ mol$.Mole fraction of solute $(x_{solute})$ = $\frac{n_{solute}}{n_{solute} + n_{solvent}}$.$x_{solute} = \frac{1}{1 + 21.70} = \frac{1}{22.70} \approx 0.044$.Therefore,the mole fraction of the solute is $0.044$.

The mole fraction of a solute in a $1$ molal ethanolic solution is:

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