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(C) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting at least one of the two

Vedclass · Accepted Answer

$\frac{11}{36}$

Vedclass · Answer

(C) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting at least one of the two numbers as $4$.The favorable outcomes are: $(1,4), (2,4), (3,4), (4,4), (5,4), (6,4), (4,1), (4,2), (4,3), (4,5), (4,6)$.Counting these,we get $n(A) = 11$.The probability $P(A)$ is given by $\frac{n(A)}{n(S)} = \frac{11}{36}$.

Two dice are thrown. Find the probability of getting at least one of the two numbers as $4$.

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