Two coins are tossed. What is the probability | vedclass

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(C) When two coins are tossed,the sample space $S$ is given by: $S = \{(H, H), (H, T), (T, H), (T, T)\}$.Total number of outcomes $n(S) = 4$.Let $E$ b

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$3/4$

Vedclass · Answer

(C) When two coins are tossed,the sample space $S$ is given by: $S = \{(H, H), (H, T), (T, H), (T, T)\}$.Total number of outcomes $n(S) = 4$.Let $E$ be the event of getting at most one head. This means getting zero heads or one head.The favorable outcomes are: $E = \{(H, T), (T, H), (T, T)\}$.Number of favorable outcomes $n(E) = 3$.The probability $P(E)$ is given by the formula $P(E) = \frac{n(E)}{n(S)}$.Therefore,$P(E) = \frac{3}{4}$.

Two coins are tossed. What is the probability of getting at most one head?

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