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(C) When two dice are thrown,the total number of outcomes is $n(S) = 6 	imes 6 = 36$.The sum of the numbers on the two dice is even if both numbers a

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$\frac{1}{2}$

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(C) When two dice are thrown,the total number of outcomes is $n(S) = 6 	imes 6 = 36$.The sum of the numbers on the two dice is even if both numbers are even or both numbers are odd.Let $A$ be the event of getting an even sum.The outcomes resulting in an even sum are:$(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6)$.Counting these,we get $n(A) = 18$.The probability $P(A) = \frac{n(A)}{n(S)} = \frac{18}{36} = \frac{1}{2}$.

Two dice are thrown. Find the probability of getting an even number as the sum.

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