$\cot 5^o - \tan 5^o - 2 \tan 10^o - 4 \tan 20^o - 8 \cot 40^o$ is equal to

  • A
    $0$
  • B
    $4 \tan 40^o$
  • C
    $8 \tan 40^o$
  • D
    $8 \cot 40^o$

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