text{cosec } A - 2 cot 2A cos A = | vedclass

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Question

(A) Given expression: $	ext{cosec } A - 2 \cot 2A \cos A$$= \frac{1}{\sin A} - \frac{2 \cos A \cos 2A}{\sin 2A}$$= \frac{1}{\sin A} - \frac{2 \cos A

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$2 \sin A$

Vedclass · Answer

(A) Given expression: $	ext{cosec } A - 2 \cot 2A \cos A$$= \frac{1}{\sin A} - \frac{2 \cos A \cos 2A}{\sin 2A}$$= \frac{1}{\sin A} - \frac{2 \cos A \cos 2A}{2 \sin A \cos A}$$= \frac{1}{\sin A} - \frac{\cos 2A}{\sin A}$$= \frac{1 - \cos 2A}{\sin A}$Using the identity $1 - \cos 2A = 2 \sin^2 A$:$= \frac{2 \sin^2 A}{\sin A}$$= 2 \sin A$.

$\text{cosec } A - 2 \cot 2A \cos A = $

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