The square root of frac{(0.75)^{3}}{1-0.75} + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the expression be $E = \frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$.First,simplify the fraction: $\frac{(0.75)^{3}}{0.25} = \frac{(0.75)

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Let the expression be $E = \frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$.First,simplify the fraction: $\frac{(0.75)^{3}}{0.25} = \frac{(0.75)^{3}}{(0.75/3)} = 3 	imes (0.75)^{2}$.Now,substitute this back into the expression: $E = 3 	imes (0.75)^{2} + 0.75^{2} + 0.75 + 1$.Combine the terms: $E = 4 	imes (0.75)^{2} + 0.75 + 1$.Calculate the values: $4 	imes (0.5625) + 0.75 + 1 = 2.25 + 0.75 + 1 = 4$.The square root of the expression is $\sqrt{4} = 2$.

The square root of $\frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$ is

Similar Questions

$\frac{250}{\sqrt{?}}=10$

Given that $\sqrt{20} = 4.472$,find the square root of $2 \frac{2}{9}$ up to two places of decimals.

$A$ General wishing to draw up his $5180$ men in the form of a solid square found that he had $4$ men less. If he could get four more men and form the solid square,the number of men in the front row is

What number should be divided by $\sqrt{0.25}$ to give the result as $25$?

$(x)^{2} \times (12)^{2} \div (48)^{2} = 81$,find the value of $x$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module