frac{(0.87)^{3}+(0.13)^{3}}{(0.87)^{2}+(0.13) | vedclass

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Question

(C) Let $a = 0.87$ and $b = 0.13$.The given expression is of the form $\frac{a^{3} + b^{3}}{a^{2} + b^{2} - ab}$.Using the algebraic identity $a^{3} +

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) Let $a = 0.87$ and $b = 0.13$.The given expression is of the form $\frac{a^{3} + b^{3}}{a^{2} + b^{2} - ab}$.Using the algebraic identity $a^{3} + b^{3} = (a + b)(a^{2} + b^{2} - ab)$,we can simplify the expression:$\frac{(a + b)(a^{2} + b^{2} - ab)}{a^{2} + b^{2} - ab} = a + b$.Substituting the values of $a$ and $b$ back into the simplified expression:$0.87 + 0.13 = 1$.Therefore,the value of the expression is $1$.

$\frac{(0.87)^{3}+(0.13)^{3}}{(0.87)^{2}+(0.13)^{2}-(0.87) \times(0.13)}$ is equal to

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