15 frac{2}{3} times 3 frac{1}{6} + 6 frac{1}{ | vedclass

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Question

(D) Convert the mixed fractions into improper fractions:$15 \frac{2}{3} = \frac{47}{3}$,$3 \frac{1}{6} = \frac{19}{6}$,$6 \frac{1}{3} = \frac{19}{3}$,

Vedclass · Accepted Answer

$44 \frac{5}{9}$

Vedclass · Answer

(D) Convert the mixed fractions into improper fractions:$15 \frac{2}{3} = \frac{47}{3}$,$3 \frac{1}{6} = \frac{19}{6}$,$6 \frac{1}{3} = \frac{19}{3}$,$11 \frac{7}{18} = \frac{205}{18}$.Let the missing value be $x$.The equation becomes: $\frac{47}{3} 	imes \frac{19}{6} + \frac{19}{3} = \frac{205}{18} + x$.Calculate the product: $\frac{47 	imes 19}{3 	imes 6} = \frac{893}{18}$.Now,$\frac{893}{18} + \frac{19}{3} = \frac{205}{18} + x$.Convert $\frac{19}{3}$ to a fraction with denominator $18$: $\frac{19 	imes 6}{3 	imes 6} = \frac{114}{18}$.So,$\frac{893}{18} + \frac{114}{18} = \frac{205}{18} + x$.$\frac{1007}{18} = \frac{205}{18} + x$.$x = \frac{1007}{18} - \frac{205}{18} = \frac{802}{18}$.Simplifying $\frac{802}{18}$ by dividing by $2$: $\frac{401}{9}$.Converting $\frac{401}{9}$ to a mixed fraction: $44 \frac{5}{9}$.

$15 \frac{2}{3} \times 3 \frac{1}{6} + 6 \frac{1}{3} = 11 \frac{7}{18} + ?$

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