(90 + 91 + 92 + ldots + 110) is equal to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given series is an arithmetic progression where the first term $a = 90$,the last term $l = 110$,and the number of terms $n$ is calculated as $

Vedclass · Accepted Answer

$2100$

Vedclass · Answer

(A) The given series is an arithmetic progression where the first term $a = 90$,the last term $l = 110$,and the number of terms $n$ is calculated as $n = (110 - 90) + 1 = 21$.The sum of an arithmetic progression is given by the formula $S_n = \frac{n}{2}(a + l)$.Substituting the values: $S_{21} = \frac{21}{2}(90 + 110)$.$S_{21} = \frac{21}{2}(200)$.$S_{21} = 21 	imes 100 = 2100$.

$(90 + 91 + 92 + \ldots + 110)$ is equal to

Similar Questions

$42 \%$ of a number is $357$. What is $63 \%$ of that number?

$47 \times 251 - 13343 + 1547 = ?$

$(6990 \div 15) \times (468 \div 18) = ?$

$\left[(72)^{2} \div 36+(?)^{2}\right] \div 5=45$

Divide $50$ into two parts so that the sum of their reciprocals is $1/12$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module