(8.5 times 8.5 + 93.5 + 5.5 times 5.5)^{1/2} | vedclass

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Question

(B) Given expression: $(8.5 	imes 8.5 + 93.5 + 5.5 	imes 5.5)^{1/2}$We can rewrite $93.5$ as $2 	imes 8.5 	imes 5.5$ because $2 	imes 8.5 = 17$ a

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(B) Given expression: $(8.5 	imes 8.5 + 93.5 + 5.5 	imes 5.5)^{1/2}$We can rewrite $93.5$ as $2 	imes 8.5 	imes 5.5$ because $2 	imes 8.5 = 17$ and $17 	imes 5.5 = 93.5$.So,the expression becomes: $[(8.5)^2 + 2 	imes 8.5 	imes 5.5 + (5.5)^2]^{1/2}$Using the algebraic identity $(a + b)^2 = a^2 + 2ab + b^2$,where $a = 8.5$ and $b = 5.5$:$[(8.5 + 5.5)^2]^{1/2} = (14^2)^{1/2} = 14$.

$(8.5 \times 8.5 + 93.5 + 5.5 \times 5.5)^{1/2}$ is equal to ...........

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