2 cans have the same height equal to 21, cm. | vedclass

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(B) The volume of the cylindrical can is given by $V_{cyl} = \pi r^2 h$.Given $h = 21\, cm$ and diameter $d = 10\, cm$,so radius $r = 5\, cm$.$V_{cyl}

Vedclass · Accepted Answer

$450$

Vedclass · Answer

(B) The volume of the cylindrical can is given by $V_{cyl} = \pi r^2 h$.Given $h = 21\, cm$ and diameter $d = 10\, cm$,so radius $r = 5\, cm$.$V_{cyl} = \frac{22}{7} 	imes (5)^2 	imes 21 = 22 	imes 25 	imes 3 = 1650\, cm^3$.The volume of the square-based can is given by $V_{sq} = (	ext{side})^2 	imes h$.Given side $= 10\, cm$ and $h = 21\, cm$.$V_{sq} = (10)^2 	imes 21 = 100 	imes 21 = 2100\, cm^3$.The difference in their capacities is $V_{sq} - V_{cyl} = 2100 - 1650 = 450\, cm^3$.

$2$ cans have the same height equal to $21\, cm$. One can is cylindrical,the diameter of whose base is $10\, cm$. The other can has a square base of side $10\, cm$. What is the difference between their capacities? (in $cm^3$)

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