$P$ and $Q$ are $27 \, km$ apart. Two trains with speeds of $24 \, km/h$ and $18 \, km/h$ respectively start simultaneously from $P$ and $Q$ and travel in the same direction. They meet at a point $R$ beyond $Q$. The distance $QR$ is (in $km$):

In covering a certain distance,the speeds of $A$ and $B$ are in the ratio of $3:4$. $A$ takes $30 \text{ minutes}$ more than $B$ to reach the destination. The time taken by $A$ to reach the destination is (in $\text{hours}$):

$A$ boy goes to the school with the speed of $3 \, km/h$ and returns with the speed of $2 \, km/h$. If he takes $5 \, hours$ in all,then the distance (in $km$) between the village and the school is:

$A$ train crosses a pole in $10 \, s$ and a platform,which is $40 \%$ longer than the length of the train,in $24 \, s$. If the length of the platform is $140 \, m$,what is the speed of the train in $m/s$?

If a man walks at the rate of $5\, km/h$,he misses a train by $7\, minutes$. However,if he walks at the rate of $6\, km/h$,he reaches the station $5\, minutes$ before the arrival of the train. The distance covered by him to reach the station is (in $km$)

$A$ thief is stopped by a policeman from a distance of $150\, m$. When the policeman starts the chase,the thief also starts running. Assuming the speed of the thief as $7\, km/h$ and that of the policeman as $9\, km/h$,how far would the thief have run before he is overtaken by the policeman? (in $m$)